2q^2-110q+900=0

Solution for 2q^2-110q+900=0 equation:

2q^2-110q+900=0

a = 2; b = -110; c = +900;
Δ = b2-4ac
Δ = -1102-4·2·900
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4900}=70$
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-110)-70}{2*2}=\frac{40}{4}
=10
$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-110)+70}{2*2}=\frac{180}{4}
=45
$